关键词库的调用求解在tag列表页面判断当前tag所属模块如果
迅睿框架 更新 2019-06-29 15:34:38
华仔
华仔
POSCMS4
关键词库的调用求解，在tag列表页面判断当前tag所属模块，如果是down模块就显示1如果是news就显示2，请问判断应该怎么写
下面是tag页面的代码
<span>TAG: {$tag.name}</span>
</li>
</ul>
{if $tag.id}
<div class="row">
<div class="col-lg-12">
<div class="portlet light">
<div class="portlet-title">
<div class="caption">
<span class="caption-subject font-green">{$tag.name}</span>
</div>
</div>
<div class="portlet-body">
{$tag.content}
</div>
</div>
</div>
</div>
{/if}
<div class="row">
<!-- 调用全部内容模块,并循环输出相关内容数据 -->
{cache name=module-content return=c}
<div class="col-md-6">
<div class="portlet light">
<div class="portlet-title">
<div class="caption">
<span class="caption-subject"><a class="font-green" href="{$c.url}">{$tag.name}的{$c.name}</a></span>
</div>
</div>
<div class="portlet-body">
<ul class="list-unstyled fc-list-row">
<!-- 调用$c.dirname模块的相关tag内容 显示5条 -->
{related module=$c.dirname field=title,url tag=$tag.tags num=5}
<li><span class="badge badge-empty badge-success"></span> <a href="{$t.url}" class="title">{dr_strcut($t.title, 35)}</a></li>
{/related}
</ul>
</div>
</div>
</div>
{/cache}
{cache name=module-content return=c} {if $c.dirname == "down"} 111 {/if} {if $c.dirname == "news"} 111 {/if}