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单页栏目，自定义栏目字段下添加的多文件字段，如何转换得到URL地址
单页栏目，自定义栏目字段下添加的多文件字段，如何转换得到URL地址
回调代码
public function category_show($data) {
$rt = [
'xcxpt' => dr_share_cat_value($data['catid'], "xcxpt"),
];
return $rt;
}返回数据：
{
"code": 1,
"msg": "view",
"data": {
"xcxpt": [
{
"file": "18",
"title": "57f1a9381d4b7",
"description": ""
},
{
"file": "19",
"title": "57f1a91443710",
"description": ""
},
{
"file": "20",
"title": "57f1a941d2c80",
"description": ""
},
{
"file": "21",
"title": "57f1a9606d614",
"description": ""
}
]
}
}请问这种多图字段，回调函数应该怎么写才能把数字（file）转换成图片地址
public function category_show($data) { $aaa = dr_share_cat_value($data['catid'], "xcxpt"); foreach($aaa as $a => $aa) { $aaa[$a]['file'] = dr_get_file($aaa[$a]['file']); } $rt = [ 'xcxpt' => $aaa, ]; return $rt; }不要复制代码，先理解一下为什么这么写