如何调用当前顶级栏目下所有下级子栏目，并且当前高亮显示
迅睿框架 更新 2021-10-11 20:37:50
liyaojun998
liyaojun998
请问如何调用当前顶级栏目下所有下级子栏目并且当前高亮显示？
如图：
<h3 class="index-exhibition-famous-top content-nav-top"><a href="javascript:;">{$top.name}</a></h3> <ul class="nav nav-pills nav-stacked content-nav"> {category pid=$top.id return=c} <li class='current'><a href="{$cat.url}"><span>{$cat.name}</span></a></li> <li class=""><a href="{$c.url}" target="_self">{$c.name}</a></li> {/category} </ul>输出当前顶级栏目的下级子栏目 {category pid=$top.id return=c} 是否当前栏目：{if $c.id==$cat.id} class="active"{/if} <a href="{$c.url}">{$c.name}</a> {/category}调用后会多一条当前栏目，<h3 class="index-exhibition-famous-top content-nav-top"><a href="javascript:;">{$top.name}</a></h3> <ul class="nav nav-pills nav-stacked content-nav"> {category pid=$top.id return=c} {if $c.id==$cat.id} <li class='current'><a href='{$cat.url}'><span>{$cat.name}</span></a></li>{/if} <li class=""> <a href="{$c.url}" target="_self">{$c.name}</a></li> {/category} </ul>