网站表单提交怎么不跳转 url

迅睿框架更新 2022-01-19 13:27:44

多鱼

网站表单提交怎么不跳转 url ，显示

{"code":11,"msg":"Send successfully, we will contact you soon!!!","data":{"1":{"title":"2121","name":"1111","email":"222@qq.com","phone":"21212","message":"212121","company":"","country":"","fromurl":"","status":1,"uid":1,"inputip":"123.9.203.36-54238","inputtime":1642406892,"displayorder":0,"tableid":0,"id":11},"0":{"uid":1,"id":11},"url":"submitted_successfully.html"}}

我想跳转到 submitted_successfully.html

方案

迅睿框架联合创始人 #1 · 2022-01-17 16:18:39

说明你没有按照正确的js提交函数的方法来写。检查一下示范例子。
多鱼 #2 · 2022-01-17 16:20:29

迅睿框架联合创始人我是普通提交 <form id="myform" action="{SITE_URL}index.php?s=form&c=liuyan&m=post" method="post">
迅睿框架联合创始人 #3 · 2022-01-17 16:22:36

这个就错了
多鱼 #4 · 2022-01-17 16:23:50

迅睿框架联合创始人怎么错了
迅睿框架联合创始人 #5 · 2022-01-17 16:38:20

参考文档：《外部页面调用网站表单提交项目》
EG.Grubby #6 · 2022-01-19 13:27:32

满意答案

用自带的钩子实现跳转即可
多鱼 #7 · 2022-01-19 13:27:44

@EG.Grubby：用自带的钩子实现跳转即可